Factorising into a Single Bracket: Explanation, Examples and Questions

Factorising single brackets is required as a stand-alone algebraic skill but it can also be used for rearranging formulae and solving algebraic equations. Factorising into a single bracket is the opposite process of expanding a single bracket.

In this article you will learn how to factorise algebraic expressions into a single bracket.

What Does 'Factorising into a Single Bracket' Mean in Mathematics?

Factorising an algebraic expression into a single bracket means to divide every term of an expression by the highest common factor (HCF).

You then rewrite the expression as the product of the highest common factor and a single bracket containing two or more terms.

Expanding and Factorising Single Brackets

If that sounds confusing, don’t worry – we’ll show you plenty of examples!

How to Factorise into Single Brackets

In order to factorise into a single bracket, you need to inspect each term of the expression and find its highest common factor (HCF).

  1. Find the highest common factor of each term in the expression.
  2. Write this highest common factor outside of a set of brackets.
  3. Divide the first term of the expression by the HCF. Write this inside of the bracket.
  4. Divide the second term of the expression by the HCF. Write this inside of the bracket.
  5. If you have more than two terms, repeat this process.

Factorising Single Bracket Examples

Table Method

Like we did when expanding brackets, we can also use a table to factorise into brackets.

Example 1:

Factorise 14x + 35

Factorising Using a Table

Answer: 7(2x + 5)

Example 2: Including a Negative

Factorise 24x - 16:

Factorising a into a Single Bracket Including a Negative

Answer: 8(3x - 2)

Factorising with Unknowns in Two or More Terms

If you have variables in more than one of the terms, you also need to find the HCF of the variables.

As an example, let’s consider finding the HCF of \( 9x^2 \) and \( 15x \).

We can find the HCF of the coefficients (the numbers before the variables) and the HCF of the variables separately.

We use this HCF of \( 3x \) in the example below.

Example 3: Unknowns in Both Terms

Factorise \( 9x^2 - 15x \)

Factorising with variables in both terms

Answer: \( 3x(3x - 5) \)

Inspection Method

As you practise factorising, you’ll learn to do this simply by inspecting and may not need to use a table any more.

Example 1

Question: Factorise \( 4x + 8 \)

Step 1: Find the highest common factor (HCF) of \( 4x \) and \( 8 \).

The HCF of \( 4x \) and \( 8 \) is \( 4 \).

Step 2: Write the HCF outside of the bracket.

\( 4x + 8 = 4(\_ + \_) \)

Step 3: Find the missing values by dividing each term inside the bracket by the HCF.

\( \frac{4x}{4} = x \)

\( \frac{8}{4} = 2 \)

So \( 4x + 8 = 4(x + 2) \)

Answer: \( 4(x + 2) \)

Example 2

Question: Factorise \( 3x^2 - 9x \)

Step 1: Find the HCF of \( 3x^2 \) and \( -9x \).

The HCF of \( 3x^2 \) and \( -9x \) is \( 3x \).

Step 2: Write the HCF outside of the bracket.

\( 3x^2 - 9x = 3x(\_ - \_) \)

Step 3: Find the missing values by dividing each term inside the bracket by \( 3x \).

\( \frac{3x^2}{3x} = x \)

\( \frac{9x}{3x} = 3 \)

So \( 3x^2 - 9x = 3x(x - 3) \)

Answer: \( 3x(x - 3) \)

Example 3

Question: Factorise \( 10x^2 + 8xy \)

Step 1: Find the HCF of \( 10x^2 \) and \( 8xy \).

The HCF of \( 10 \) and \( 8 \) is \( 2 \).

The HCF of \( x^2 \) and \( xy \) is \( x \).

So the HCF of \( 10x^2 \) and \( 8xy \) is \( 2x \).

Step 2: Write \( 2x \) outside of the bracket.

\( 10x^2 + 8xy = 2x(\_ + \_) \)

Step 3: Find the missing values by dividing each term inside the bracket by \( 2x \).

\( \frac{10x^2}{2x} = 5x \)

\( \frac{8xy}{2x} = 4y \)

So \( 10x^2 + 8xy = 2x(5x + 4y) \)

Answer: \( 2x(5x + 4y) \)

Ready to practise some GCSE factorising questions?